Custom Search




2
wf/nA = 48
Wf = 7.68 oz
(5) For Rf less than 20 feet,
Vs = Vo a 6,258 ft/sec.
(6) Using Equation (28) to determine the number of fragments
having a weight greater than 1.5 oz:
Nf = NT(1  CL)
From Figure 22, for given casing geometry:
(B2NT)/W, = 0.275
N T = [0.275(220.7)(16)1/0.09 = 10,790
Determine the design Confidence Level corresponding to
Wf = 1.5 oz.
From Figure 21, CL = 0.955
Therefore, Nf = 10,790(1  0.955)
= 486 fragments.
13.
NOTATION.
Presented area of fragment, in2

A
Vent area, ft2
B

Explosive constant
Drag coefficient

CL

Confidence level
C'

Fragment distribution constant
d

Charge depth, ft
Diameter of hole in roof, ft
d

Average inside diameter of casing, in
i
(2E')l/2
 Gurney's energy constant
F

Factor to account for effect of casing on effective charge weight
H

Height, ft
2.0865


Integrated Publishing, Inc.
6230 Stone Rd, Unit Q
Port Richey, FL 34668
Phone For Parts Inquiries: (727) 4930744 Google + 