Quantcast Design of a Beam Subject to Torsion -Cont. - dm2_080135

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(6) Total web reinforcement:
AtV + Av/2 = 0.08 + 0.435.2
= 0.298 in2/ft/Leg
Use No. 4 ties at 8 in = 0.300 in2/ft/Leg
(7) Minimum tie reinforcing area:
Av(min) = Av shear alone from Example Problem a.
0.394
12
= x  
2
10
= 0.236 in2/ft/Leg < 0.300 in2/ft/Leg O.K.
Maximum spacing:
ht + bt
smax =
4
26 + 14.5
=
4
= 10.125 in > 8 in
O.K.
(8) Required area of longitudinal steel is the greater of the
two values from Equations (54a> or (54b).  Using Equation
(54a):
bt + ht
A*l = 2At x
s
14.5 + 26.0
= 2 x 0.08 x  
12
= 0.54 in2
Using Equation (54b):
1400 b s
vtu
 bt + ht
A*l  = () - 2Atx  
 fy
vtu + vu
s
2.08-118





 


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