Quantcast Design flange for rebound

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Extrapolating from Figure 6-7 of NAVFAC P-397
Xm/XE = 1.0
Thus rattained = ravailable
O.K.
(5)
Design flange for rebound.
Using NAVFAC P-397, Figure 6-8,
r -ru = -0.6
r - = -0.6(2.02)
= 1.21 psi
rrequired = r - - DL
= 1.21 - (3 x 150/123)
= 0.95 psi
M -u = r -(L)2/2
= 0.95(21.125)2/2
= 211.98 in-lb/in
Assume a = 0.04 inch
As = M -u/[fdy(d - a/2)]
= 211.98/[71,500(2.25-0.02)]
= 0.0013 in2/in
a
= Asfdy/(.85fdc'b)
= 0.0013(71500)/(.85 x 6250 x 1)
= 0.017 in
No Good
Assume a = 0.018 inch
As = 211.98/[71,500(2.25-0.009)]
= .0013 in2/in
a = 0.0013(71500)/(.85 x 6250 x 1)
= 0.017 in = 0.018 in
O.K.
Bottom layer of WWF 6 X 6 W1.4 X W1.4
Check that section of flange spanning between tee section
is not critical.
ru = 8(MN + Mp)/L2
MN = 531 in-lb/in
Mp = 373 in-lb/in
L  = 48 - 5.75 = 42.25
ru = 8(531 + 373)/42.252
= 4.05 psi
2.08-259





 


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