Quantcast Design of Door Frame

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B/ru = 432/1,676
= 0.2578
T/TN = 22.81/2.13
= 10.71
From Figure 6-7, NAVFAC P-397:
[mu] = Xm/XE
=1<3
O.K.
Xm = 1 x 0.04304
= 0.04304 in
tan [theta] = Xm/(L/2)
= 0.04304/(36/2)
= 0.002391
[theta] = 0.137deg. < 1deg.
O.K.
Check stresses at the connecting point.
[sigma] = My/I
= 271.6(103)(1.256 - 0.375)/29.37
= 8,147 psi
[tau] = VQ/Ib
= 7.776(103)(12.70)(3/8)(1.256 - 0.375/2)/
29.37(0.200)
= 6,736 psi
Effective stress at the section
([sigma]2 + [tau]2)1/2 = (8.1472 +
6,7362)1/2
= 10,571 psi <
36,000 psi O.K.
c.
Design of Door Frame
Problem:
Design the frame of the blast door described in Figure 74,
Example 6.a.
Given:
(1) Same parameters as in Example 6.a, Figure 74.
(2) Size of door opening.
(3) Surrounding wall thickness.
(4) Type of steel
2.08-288





 


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