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 (4) Area of web reinforcing for shear using Equation (45).
Av = (vu - vc) x b x s/([phi] x fy)
Assume s = 12 in.
Av = (202.7 - 99.9) x 18 x 12/(0.85 x 60,000)
= 0.435 in2/ft
(5) Web reinforcing for torsional stress using Equation (51).
(vtu - vtc) b2hs
AtV =
3[phi][alpha]t bt ht fy
where,
ht
[alpha]t = 0.66 + 0.33
< /= 1.50
bt
ht = 30.0 - 2.0 - 1.5 - 2 x 0.5/2 = 26 in
See Figure 38b.
bt = 18.0 - 1.5 - 1.5 - 2 x 0.5/2 = 14.5 in
See Figure 38b.
Therefore,
26
[alpha]t = 0.66 + 0.33 x
= 1.25 < 1.50
O.K.
14.5
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