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 ru = 8Mp/L2
= (8 x 116.5)/(17)2
= 3.22 k/ft
B/ru = 2.79/3.22 = 0.87
From Figure 6-7 of NAVFAC P-397:
[mu] = Xm/XE = 1.65 < 3 O.K.
(9) Determine XE.
XE = ru/KE
= (3.22 x 12)/39.1
= 0.99 in
Find Xm.
Xm = [mu]XE
= 1.65 x 0.99
= 1.634 in
Find end rotation, [theta].
tan [theta] = Xm/(L/2)
= 1.634/(8.5 x 12)
= 0.0160
[theta] < 1o O.K.
(10) Check for shear.
Dynamic yield stress in shear:
Fdv = 0.55Fdy
= 0.55 x 39.6
= 21.8 ksi
Dynamic shear capacity:
Vp = FdvAw
= 21.8 x 0.23 x 11.46
= 57.5 k
Maximum support shear (Table 8):
V = ruL/2
= (3.22 x 17)/2
= 27.4 k
Vp > V
O.K.
2.08-175
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