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 B/ru = 27.0/56.11
= 0.4812
T/TN = 22.81/4.859
= 4.694
From Figure 6-7, NAVFAC P-397:
[mu] = Xm/XE
= 1.2, so it satisfies the ductility ratio
criteria.
Since the response is elastic, determine the DLF.
Refer
to Figure 5.19 of Manual EM 1110-345-415.
DLF = 0.98 for T/TN = 0.349
Hence,
Xm = 0.98(27.0)(0.1694)/56.11
= 0.0799 in
tan [theta] = Xm/(L/2)
= 0.0799/(15.75/2)
= 0.01015
[theta] = 0.581deg. < 2deg.
O.K.
(13) Design of supporting flexural element.
Assume a channel C6 x 8.2 and attach to plate as shown in
Figure 77.
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